Base | Representation |
---|---|
bin | 11111001010010110101… |
… | …100110001000111001111 |
3 | 21120201101101100101221121 |
4 | 133022112230301013033 |
5 | 240041113020000221 |
6 | 4315431121541411 |
7 | 310466301636163 |
oct | 37122654610717 |
9 | 7521341311847 |
10 | 2141422031311 |
11 | 756198a01112 |
12 | 2a7031aa4867 |
13 | 126c209199c4 |
14 | 75906cc6ca3 |
15 | 3aa83996a41 |
hex | 1f296b311cf |
2141422031311 has 2 divisors, whose sum is σ = 2141422031312. Its totient is φ = 2141422031310.
The previous prime is 2141422031293. The next prime is 2141422031317. The reversal of 2141422031311 is 1131302241412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2141422031311 - 25 = 2141422031279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2141422031317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070711015655 + 1070711015656.
It is an arithmetic number, because the mean of its divisors is an integer number (1070711015656).
Almost surely, 22141422031311 is an apocalyptic number.
2141422031311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141422031311 is an equidigital number, since it uses as much as digits as its factorization.
2141422031311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2141422031311 its reverse (1131302241412), we get a palindrome (3272724272723).
The spelling of 2141422031311 in words is "two trillion, one hundred forty-one billion, four hundred twenty-two million, thirty-one thousand, three hundred eleven".
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