Base | Representation |
---|---|
bin | 11111001010011100000… |
… | …000010001100100011011 |
3 | 21120201121120211001122212 |
4 | 133022130000101210123 |
5 | 240041303310443232 |
6 | 4315444021305335 |
7 | 310501432264532 |
oct | 37123400214433 |
9 | 7521546731585 |
10 | 2141511031067 |
11 | 756234169a31 |
12 | 2a705786524b |
13 | 126c361ab595 |
14 | 75914a53319 |
15 | 3aa8b6c6eb2 |
hex | 1f29c01191b |
2141511031067 has 2 divisors, whose sum is σ = 2141511031068. Its totient is φ = 2141511031066.
The previous prime is 2141511031063. The next prime is 2141511031069. The reversal of 2141511031067 is 7601301151412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2141511031067 - 22 = 2141511031063 is a prime.
It is a super-3 number, since 3×21415110310673 (a number of 38 digits) contains 333 as substring.
Together with 2141511031069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2141511031063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070755515533 + 1070755515534.
It is an arithmetic number, because the mean of its divisors is an integer number (1070755515534).
Almost surely, 22141511031067 is an apocalyptic number.
2141511031067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141511031067 is an equidigital number, since it uses as much as digits as its factorization.
2141511031067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 32.
Adding to 2141511031067 its reverse (7601301151412), we get a palindrome (9742812182479).
The spelling of 2141511031067 in words is "two trillion, one hundred forty-one billion, five hundred eleven million, thirty-one thousand, sixty-seven".
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