Base | Representation |
---|---|
bin | 1100011110011010000… |
… | …0001101011111011011 |
3 | 202111012101000121000221 |
4 | 3013212200031133123 |
5 | 12002412033213201 |
6 | 242242454140511 |
7 | 21325031023324 |
oct | 3074640153733 |
9 | 674171017027 |
10 | 214320601051 |
11 | 82990434787 |
12 | 35653651737 |
13 | 1729718c9cb |
14 | a531db144b |
15 | 58957d54a1 |
hex | 31e680d7db |
214320601051 has 2 divisors, whose sum is σ = 214320601052. Its totient is φ = 214320601050.
The previous prime is 214320601021. The next prime is 214320601063. The reversal of 214320601051 is 150106023412.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214320601051 - 29 = 214320600539 is a prime.
It is a super-3 number, since 3×2143206010513 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (214320601021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107160300525 + 107160300526.
It is an arithmetic number, because the mean of its divisors is an integer number (107160300526).
Almost surely, 2214320601051 is an apocalyptic number.
214320601051 is a deficient number, since it is larger than the sum of its proper divisors (1).
214320601051 is an equidigital number, since it uses as much as digits as its factorization.
214320601051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 214320601051 its reverse (150106023412), we get a palindrome (364426624463).
The spelling of 214320601051 in words is "two hundred fourteen billion, three hundred twenty million, six hundred one thousand, fifty-one".
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