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214322213401000 = 2353214322213401
BaseRepresentation
bin110000101110110011000111…
…011001011011000110101000
31001002212000002112220201200121
4300232303013121123012220
5211042423343112313000
62035454133212013024
763100161146466625
oct6056630731330650
91032760075821617
10214322213401000
11623205a4107181
12200550b7761174
139278662160593
143acd37144534c
1519ba02c87eb1a
hexc2ecc765b1a8

214322213401000 has 32 divisors (see below), whose sum is σ = 501513979360680. Its totient is φ = 85728885360000.

The previous prime is 214322213400989. The next prime is 214322213401003. The reversal of 214322213401000 is 104312223412.

214322213401000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 77982074916516 + 136340138484484 = 8830746^2 + 11676478^2 .

It is a super-2 number, since 2×2143222134010002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (214322213401003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107161105701 + ... + 107161107700.

Almost surely, 2214322213401000 is an apocalyptic number.

214322213401000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

214322213401000 is an abundant number, since it is smaller than the sum of its proper divisors (287191765959680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

214322213401000 is a wasteful number, since it uses less digits than its factorization.

214322213401000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214322213422 (or 214322213408 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 214322213401000 its reverse (104312223412), we get a palindrome (214426525624412).

The spelling of 214322213401000 in words is "two hundred fourteen trillion, three hundred twenty-two billion, two hundred thirteen million, four hundred one thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 214322213401 428644426802 857288853604 1071611067005 1714577707208 2143222134010 4286444268020 5358055335025 8572888536040 10716110670050 21432221340100 26790276675125 42864442680200 53580553350250 107161106700500 214322213401000