Base | Representation |
---|---|
bin | 11111001100000010011… |
… | …110000111110001111111 |
3 | 21120220001101121101212212 |
4 | 133030002132013301333 |
5 | 240103313403200302 |
6 | 4320330351451035 |
7 | 310562145350615 |
oct | 37140236076177 |
9 | 7526041541785 |
10 | 2143230131327 |
11 | 756a3659844a |
12 | 2a7457526a7b |
13 | 12714b3b487c |
14 | 75a390ab6b5 |
15 | 3ab3c5a0052 |
hex | 1f302787c7f |
2143230131327 has 2 divisors, whose sum is σ = 2143230131328. Its totient is φ = 2143230131326.
The previous prime is 2143230131303. The next prime is 2143230131369. The reversal of 2143230131327 is 7231310323412.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2143230131327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2143230131293 and 2143230131302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2143230131387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071615065663 + 1071615065664.
It is an arithmetic number, because the mean of its divisors is an integer number (1071615065664).
Almost surely, 22143230131327 is an apocalyptic number.
2143230131327 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143230131327 is an equidigital number, since it uses as much as digits as its factorization.
2143230131327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 2143230131327 its reverse (7231310323412), we get a palindrome (9374540454739).
The spelling of 2143230131327 in words is "two trillion, one hundred forty-three billion, two hundred thirty million, one hundred thirty-one thousand, three hundred twenty-seven".
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