Search a number
-
+
214340122021 is a prime number
BaseRepresentation
bin1100011110011110101…
…0101011010110100101
3202111020201202100202211
43013213222223112211
512002432032401041
6242244432403421
721325355655634
oct3074752532645
9674221670684
10214340122021
11829a0458113
123565a0a6571
131729b23608c
14a53481351b
15589738e481
hex31e7aab5a5

214340122021 has 2 divisors, whose sum is σ = 214340122022. Its totient is φ = 214340122020.

The previous prime is 214340122019. The next prime is 214340122067. The reversal of 214340122021 is 120221043412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 192321717025 + 22018404996 = 438545^2 + 148386^2 .

It is a cyclic number.

It is not a de Polignac number, because 214340122021 - 21 = 214340122019 is a prime.

Together with 214340122019, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 214340121983 and 214340122001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214340122921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107170061010 + 107170061011.

It is an arithmetic number, because the mean of its divisors is an integer number (107170061011).

Almost surely, 2214340122021 is an apocalyptic number.

It is an amenable number.

214340122021 is a deficient number, since it is larger than the sum of its proper divisors (1).

214340122021 is an equidigital number, since it uses as much as digits as its factorization.

214340122021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 214340122021 its reverse (120221043412), we get a palindrome (334561165433).

The spelling of 214340122021 in words is "two hundred fourteen billion, three hundred forty million, one hundred twenty-two thousand, twenty-one".