Base | Representation |
---|---|
bin | 1100011110100010001… |
… | …0011001011101000101 |
3 | 202111021202020110110122 |
4 | 3013220202121131011 |
5 | 12002444302310043 |
6 | 242250113431325 |
7 | 21325624063133 |
oct | 3075042313505 |
9 | 674252213418 |
10 | 214354728773 |
11 | 829a8724409 |
12 | 35662b6b545 |
13 | 172a127b723 |
14 | a536736753 |
15 | 58987c7368 |
hex | 31e8899745 |
214354728773 has 2 divisors, whose sum is σ = 214354728774. Its totient is φ = 214354728772.
The previous prime is 214354728691. The next prime is 214354728859. The reversal of 214354728773 is 377827453412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 170897906404 + 43456822369 = 413398^2 + 208463^2 .
It is a cyclic number.
It is not a de Polignac number, because 214354728773 - 218 = 214354466629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214354728173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107177364386 + 107177364387.
It is an arithmetic number, because the mean of its divisors is an integer number (107177364387).
Almost surely, 2214354728773 is an apocalyptic number.
It is an amenable number.
214354728773 is a deficient number, since it is larger than the sum of its proper divisors (1).
214354728773 is an equidigital number, since it uses as much as digits as its factorization.
214354728773 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7902720, while the sum is 53.
The spelling of 214354728773 in words is "two hundred fourteen billion, three hundred fifty-four million, seven hundred twenty-eight thousand, seven hundred seventy-three".
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