Base | Representation |
---|---|
bin | 11111001100110111000… |
… | …010111100111000001111 |
3 | 21120222022212101012022120 |
4 | 133030313002330320033 |
5 | 240112120210414411 |
6 | 4320554101344023 |
7 | 310623046001160 |
oct | 37146702747017 |
9 | 7528285335276 |
10 | 2144112201231 |
11 | 757349493640 |
12 | 2a7662a08013 |
13 | 12725c071020 |
14 | 75ac02bb767 |
15 | 3ab8ec39106 |
hex | 1f3370bce0f |
2144112201231 has 32 divisors (see below), whose sum is σ = 3838410659328. Its totient is φ = 1028145709440.
The previous prime is 2144112201163. The next prime is 2144112201233. The reversal of 2144112201231 is 1321022114412.
It is not a de Polignac number, because 2144112201231 - 211 = 2144112199183 is a prime.
It is a super-2 number, since 2×21441122012312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2144112201233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 356992036 + ... + 356998041.
It is an arithmetic number, because the mean of its divisors is an integer number (119950333104).
Almost surely, 22144112201231 is an apocalyptic number.
2144112201231 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2144112201231 is a deficient number, since it is larger than the sum of its proper divisors (1694298458097).
2144112201231 is a wasteful number, since it uses less digits than its factorization.
2144112201231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 713990111.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 2144112201231 its reverse (1321022114412), we get a palindrome (3465134315643).
The spelling of 2144112201231 in words is "two trillion, one hundred forty-four billion, one hundred twelve million, two hundred one thousand, two hundred thirty-one".
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