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2144214130021 is a prime number
BaseRepresentation
bin11111001100111101000…
…111110001110101100101
321120222120222011201022221
4133030331013301311211
5240112322304130041
64321012142152341
7310625424245515
oct37147507616545
97528528151287
102144214130021
117573a0a82207
122a7690b826b1
1312727720b712
1475acda51845
153ab98b702d1
hex1f33d1f1d65

2144214130021 has 2 divisors, whose sum is σ = 2144214130022. Its totient is φ = 2144214130020.

The previous prime is 2144214130013. The next prime is 2144214130043. The reversal of 2144214130021 is 1200314124412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1415828692996 + 728385437025 = 1189886^2 + 853455^2 .

It is a cyclic number.

It is not a de Polignac number, because 2144214130021 - 23 = 2144214130013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2144214160021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072107065010 + 1072107065011.

It is an arithmetic number, because the mean of its divisors is an integer number (1072107065011).

Almost surely, 22144214130021 is an apocalyptic number.

It is an amenable number.

2144214130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

2144214130021 is an equidigital number, since it uses as much as digits as its factorization.

2144214130021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2144214130021 its reverse (1200314124412), we get a palindrome (3344528254433).

The spelling of 2144214130021 in words is "two trillion, one hundred forty-four billion, two hundred fourteen million, one hundred thirty thousand, twenty-one".