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21443055433 is a prime number
BaseRepresentation
bin10011111110000110…
…110000111101001001
32001100101220002011021
4103332012300331021
5322403410233213
613503435032441
71356243651412
oct237606607511
961311802137
1021443055433
119104055a18
1241a529b721
13203964c8a7
141075c04809
158577b7d8d
hex4fe1b0f49

21443055433 has 2 divisors, whose sum is σ = 21443055434. Its totient is φ = 21443055432.

The previous prime is 21443055427. The next prime is 21443055437. The reversal of 21443055433 is 33455034412.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14841817929 + 6601237504 = 121827^2 + 81248^2 .

It is a cyclic number.

It is not a de Polignac number, because 21443055433 - 229 = 20906184521 is a prime.

It is not a weakly prime, because it can be changed into another prime (21443055437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10721527716 + 10721527717.

It is an arithmetic number, because the mean of its divisors is an integer number (10721527717).

Almost surely, 221443055433 is an apocalyptic number.

It is an amenable number.

21443055433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21443055433 is an equidigital number, since it uses as much as digits as its factorization.

21443055433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 34.

Adding to 21443055433 its reverse (33455034412), we get a palindrome (54898089845).

The spelling of 21443055433 in words is "twenty-one billion, four hundred forty-three million, fifty-five thousand, four hundred thirty-three".