Base | Representation |
---|---|
bin | 11111001101101111001… |
… | …000001111101100101101 |
3 | 21121001202102212110210112 |
4 | 133031233020033230231 |
5 | 240121032044110013 |
6 | 4321231312345405 |
7 | 310655262423440 |
oct | 37155710175455 |
9 | 7531672773715 |
10 | 2145053113133 |
11 | 757791619687 |
12 | 2a7885b45265 |
13 | 12737bc90328 |
14 | 75b6d247657 |
15 | 3abe7647ba8 |
hex | 1f36f20fb2d |
2145053113133 has 32 divisors (see below), whose sum is σ = 2599847470080. Its totient is φ = 1731557053440.
The previous prime is 2145053113127. The next prime is 2145053113213. The reversal of 2145053113133 is 3313113505412.
It is a cyclic number.
It is not a de Polignac number, because 2145053113133 - 26 = 2145053113069 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2145053113133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2145053113123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 104498 + ... + 2073891.
It is an arithmetic number, because the mean of its divisors is an integer number (81245233440).
Almost surely, 22145053113133 is an apocalyptic number.
It is an amenable number.
2145053113133 is a deficient number, since it is larger than the sum of its proper divisors (454794356947).
2145053113133 is a wasteful number, since it uses less digits than its factorization.
2145053113133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2178557.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 2145053113133 its reverse (3313113505412), we get a palindrome (5458166618545).
The spelling of 2145053113133 in words is "two trillion, one hundred forty-five billion, fifty-three million, one hundred thirteen thousand, one hundred thirty-three".
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