Base | Representation |
---|---|
bin | 10100000001000010… |
… | …101010000001101111 |
3 | 2001110211120110220012 |
4 | 110001002222001233 |
5 | 323004012411002 |
6 | 13512354443435 |
7 | 1360412423201 |
oct | 240102520157 |
9 | 61424513805 |
10 | 21492310127 |
11 | 9129937782 |
12 | 41b989357b |
13 | 2046906992 |
14 | 107c586771 |
15 | 85bc96d52 |
hex | 5010aa06f |
21492310127 has 2 divisors, whose sum is σ = 21492310128. Its totient is φ = 21492310126.
The previous prime is 21492310117. The next prime is 21492310153. The reversal of 21492310127 is 72101329412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21492310127 - 28 = 21492309871 is a prime.
It is a super-2 number, since 2×214923101272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21492310093 and 21492310102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21492310117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10746155063 + 10746155064.
It is an arithmetic number, because the mean of its divisors is an integer number (10746155064).
Almost surely, 221492310127 is an apocalyptic number.
21492310127 is a deficient number, since it is larger than the sum of its proper divisors (1).
21492310127 is an equidigital number, since it uses as much as digits as its factorization.
21492310127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 21492310127 its reverse (72101329412), we get a palindrome (93593639539).
The spelling of 21492310127 in words is "twenty-one billion, four hundred ninety-two million, three hundred ten thousand, one hundred twenty-seven".
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