Base | Representation |
---|---|
bin | 11111010001101111000… |
… | …111111100011011101111 |
3 | 21121110211202110102001202 |
4 | 133101233013330123233 |
5 | 240203331042022034 |
6 | 4323221415000115 |
7 | 311166563400065 |
oct | 37215707743357 |
9 | 7543752412052 |
10 | 2149348001519 |
11 | 759595a05914 |
12 | 2a868436903b |
13 | 1278b4a0ccc4 |
14 | 76059800035 |
15 | 3ad9971c47e |
hex | 1f46f1fc6ef |
2149348001519 has 2 divisors, whose sum is σ = 2149348001520. Its totient is φ = 2149348001518.
The previous prime is 2149348001459. The next prime is 2149348001611. The reversal of 2149348001519 is 9151008439412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2149348001519 - 216 = 2149347935983 is a prime.
It is a super-2 number, since 2×21493480015192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2149348001719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074674000759 + 1074674000760.
It is an arithmetic number, because the mean of its divisors is an integer number (1074674000760).
Almost surely, 22149348001519 is an apocalyptic number.
2149348001519 is a deficient number, since it is larger than the sum of its proper divisors (1).
2149348001519 is an equidigital number, since it uses as much as digits as its factorization.
2149348001519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 47.
The spelling of 2149348001519 in words is "two trillion, one hundred forty-nine billion, three hundred forty-eight million, one thousand, five hundred nineteen".
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