214953941 has 2 divisors, whose sum is σ = 214953942. Its totient is φ = 214953940.

The previous prime is 214953919. The next prime is 214953961. The reversal of 214953941 is 149359412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117635716 + 97318225 = 10846^2 + 9865^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-214953941 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 214953895 and 214953904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214953901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107476970 + 107476971.

It is an arithmetic number, because the mean of its divisors is an integer number (107476971).

Almost surely, 2^214953941 is an apocalyptic number.

It is an amenable number.

214953941 is a deficient number, since it is larger than the sum of its proper divisors (1).

214953941 is an equidigital number, since it uses as much as digits as its factorization.

214953941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38880, while the sum is 38.

The square root of 214953941 is about 14661.3076156256. The cubic root of 214953941 is about 599.0298590749.

The spelling of 214953941 in words is "two hundred fourteen million, nine hundred fifty-three thousand, nine hundred forty-one".