Base | Representation |
---|---|
bin | 11111010011011110001… |
… | …100110100010110101100 |
3 | 21121122122122001111011110 |
4 | 133103132030310112230 |
5 | 240221140124100444 |
6 | 4324130345152020 |
7 | 311264012321310 |
oct | 37233614642654 |
9 | 7548578044143 |
10 | 2151211550124 |
11 | 75a36192452a |
12 | 2a8b0448b610 |
13 | 127b20b202a0 |
14 | 761950d9b40 |
15 | 3ae58129cb9 |
hex | 1f4de3345ac |
2151211550124 has 96 divisors (see below), whose sum is σ = 6193400851456. Its totient is φ = 565923283200.
The previous prime is 2151211550119. The next prime is 2151211550161. The reversal of 2151211550124 is 4210551121512.
It is a super-2 number, since 2×21512115501242 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2151211550091 and 2151211550100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2047552 + ... + 2914599.
Almost surely, 22151211550124 is an apocalyptic number.
It is an amenable number.
2151211550124 is an abundant number, since it is smaller than the sum of its proper divisors (4042189301332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2151211550124 is a wasteful number, since it uses less digits than its factorization.
2151211550124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4962575 (or 4962573 counting only the distinct ones).
The product of its (nonzero) digits is 4000, while the sum is 30.
Adding to 2151211550124 its reverse (4210551121512), we get a palindrome (6361762671636).
The spelling of 2151211550124 in words is "two trillion, one hundred fifty-one billion, two hundred eleven million, five hundred fifty thousand, one hundred twenty-four".
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