Base | Representation |
---|---|
bin | 11111010011011110010… |
… | …011001001111000000101 |
3 | 21121122122202011212122121 |
4 | 133103132103021320011 |
5 | 240221141040224031 |
6 | 4324130444525541 |
7 | 311264032410031 |
oct | 37233623117005 |
9 | 7548582155577 |
10 | 2151213211141 |
11 | 75a362859475 |
12 | 2a8b04b508b1 |
13 | 127b21282337 |
14 | 7619540d1c1 |
15 | 3ae58357011 |
hex | 1f4de4c9e05 |
2151213211141 has 2 divisors, whose sum is σ = 2151213211142. Its totient is φ = 2151213211140.
The previous prime is 2151213211123. The next prime is 2151213211207. The reversal of 2151213211141 is 1411123121512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2148777788641 + 2435422500 = 1465871^2 + 49350^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151213211141 - 25 = 2151213211109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151213211111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075606605570 + 1075606605571.
It is an arithmetic number, because the mean of its divisors is an integer number (1075606605571).
Almost surely, 22151213211141 is an apocalyptic number.
It is an amenable number.
2151213211141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151213211141 is an equidigital number, since it uses as much as digits as its factorization.
2151213211141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 480, while the sum is 25.
Adding to 2151213211141 its reverse (1411123121512), we get a palindrome (3562336332653).
The spelling of 2151213211141 in words is "two trillion, one hundred fifty-one billion, two hundred thirteen million, two hundred eleven thousand, one hundred forty-one".
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