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2151213211141 is a prime number
BaseRepresentation
bin11111010011011110010…
…011001001111000000101
321121122122202011212122121
4133103132103021320011
5240221141040224031
64324130444525541
7311264032410031
oct37233623117005
97548582155577
102151213211141
1175a362859475
122a8b04b508b1
13127b21282337
147619540d1c1
153ae58357011
hex1f4de4c9e05

2151213211141 has 2 divisors, whose sum is σ = 2151213211142. Its totient is φ = 2151213211140.

The previous prime is 2151213211123. The next prime is 2151213211207. The reversal of 2151213211141 is 1411123121512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2148777788641 + 2435422500 = 1465871^2 + 49350^2 .

It is a cyclic number.

It is not a de Polignac number, because 2151213211141 - 25 = 2151213211109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2151213211111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075606605570 + 1075606605571.

It is an arithmetic number, because the mean of its divisors is an integer number (1075606605571).

Almost surely, 22151213211141 is an apocalyptic number.

It is an amenable number.

2151213211141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151213211141 is an equidigital number, since it uses as much as digits as its factorization.

2151213211141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 480, while the sum is 25.

Adding to 2151213211141 its reverse (1411123121512), we get a palindrome (3562336332653).

The spelling of 2151213211141 in words is "two trillion, one hundred fifty-one billion, two hundred thirteen million, two hundred eleven thousand, one hundred forty-one".