Base | Representation |
---|---|
bin | 1001110010000110000001… |
… | …10101000011010101001010 |
3 | 2211011120100022212201012221 |
4 | 10321003000311003111022 |
5 | 10304424424411213424 |
6 | 113430401410524254 |
7 | 4350136050262414 |
oct | 471030065032512 |
9 | 84146308781187 |
10 | 21512431351114 |
11 | 6944409740520 |
12 | 24b530589668a |
13 | c007c902c3b2 |
14 | 5452c890b9b4 |
15 | 2748c37a89e4 |
hex | 1390c0d4354a |
21512431351114 has 32 divisors (see below), whose sum is σ = 37607964019200. Its totient is φ = 9125461833840.
The previous prime is 21512431351069. The next prime is 21512431351141. The reversal of 21512431351114 is 41115313421512.
It is a super-3 number, since 3×215124313511143 (a number of 41 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21512431351114.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 384040254 + ... + 384096265.
It is an arithmetic number, because the mean of its divisors is an integer number (1175248875600).
Almost surely, 221512431351114 is an apocalyptic number.
21512431351114 is a deficient number, since it is larger than the sum of its proper divisors (16095532668086).
21512431351114 is a wasteful number, since it uses less digits than its factorization.
21512431351114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768136618.
The product of its digits is 14400, while the sum is 34.
Adding to 21512431351114 its reverse (41115313421512), we get a palindrome (62627744772626).
The spelling of 21512431351114 in words is "twenty-one trillion, five hundred twelve billion, four hundred thirty-one million, three hundred fifty-one thousand, one hundred fourteen".
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