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21512653410341 is a prime number
BaseRepresentation
bin1001110010000110011100…
…00100001001000000100101
32211011120220210201111012202
410321003032010021000211
510304430403233112331
6113430435422224245
74350144414613412
oct471031604110045
984146823644182
1021512653410341
11694451301a945
1224b5368125085
13c0083303b1a2
1454530a1d3109
152748d801decb
hex1390ce109025

21512653410341 has 2 divisors, whose sum is σ = 21512653410342. Its totient is φ = 21512653410340.

The previous prime is 21512653410307. The next prime is 21512653410383. The reversal of 21512653410341 is 14301435621512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20085894829441 + 1426758580900 = 4481729^2 + 1194470^2 .

It is a cyclic number.

It is not a de Polignac number, because 21512653410341 - 26 = 21512653410277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21512653410295 and 21512653410304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21512653410301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756326705170 + 10756326705171.

It is an arithmetic number, because the mean of its divisors is an integer number (10756326705171).

Almost surely, 221512653410341 is an apocalyptic number.

It is an amenable number.

21512653410341 is a deficient number, since it is larger than the sum of its proper divisors (1).

21512653410341 is an equidigital number, since it uses as much as digits as its factorization.

21512653410341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 21512653410341 in words is "twenty-one trillion, five hundred twelve billion, six hundred fifty-three million, four hundred ten thousand, three hundred forty-one".