Base | Representation |
---|---|
bin | 1001110010001000000011… |
… | …01110110101110110110111 |
3 | 2211011200011012211002211211 |
4 | 10321010001232311312313 |
5 | 10304434142140221403 |
6 | 113431101425342251 |
7 | 4350205041556621 |
oct | 471040156656667 |
9 | 84150135732754 |
10 | 21513520242103 |
11 | 694491835842a |
12 | 24b556a497987 |
13 | c009407c07a6 |
14 | 54538d397c11 |
15 | 27493919806d |
hex | 139101bb5db7 |
21513520242103 has 2 divisors, whose sum is σ = 21513520242104. Its totient is φ = 21513520242102.
The previous prime is 21513520242079. The next prime is 21513520242161. The reversal of 21513520242103 is 30124202531512.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21513520242103 - 213 = 21513520233911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21513520242163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756760121051 + 10756760121052.
It is an arithmetic number, because the mean of its divisors is an integer number (10756760121052).
Almost surely, 221513520242103 is an apocalyptic number.
21513520242103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21513520242103 is an equidigital number, since it uses as much as digits as its factorization.
21513520242103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 21513520242103 its reverse (30124202531512), we get a palindrome (51637722773615).
The spelling of 21513520242103 in words is "twenty-one trillion, five hundred thirteen billion, five hundred twenty million, two hundred forty-two thousand, one hundred three".
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