Base | Representation |
---|---|
bin | 1001110010001000111110… |
… | …01000001000100000010111 |
3 | 2211011201102120210200212112 |
4 | 10321010133020020200113 |
5 | 10304441144413130401 |
6 | 113431222403541235 |
7 | 4350223210464056 |
oct | 471043710104027 |
9 | 84151376720775 |
10 | 21514013411351 |
11 | 694505077981a |
12 | 24b568768a81b |
13 | c009bba23706 |
14 | 5453d8a9239d |
15 | 2749676123bb |
hex | 13911f208817 |
21514013411351 has 2 divisors, whose sum is σ = 21514013411352. Its totient is φ = 21514013411350.
The previous prime is 21514013411323. The next prime is 21514013411393. The reversal of 21514013411351 is 15311431041512.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21514013411351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21514013411321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757006705675 + 10757006705676.
It is an arithmetic number, because the mean of its divisors is an integer number (10757006705676).
Almost surely, 221514013411351 is an apocalyptic number.
21514013411351 is a deficient number, since it is larger than the sum of its proper divisors (1).
21514013411351 is an equidigital number, since it uses as much as digits as its factorization.
21514013411351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 21514013411351 its reverse (15311431041512), we get a palindrome (36825444452863).
The spelling of 21514013411351 in words is "twenty-one trillion, five hundred fourteen billion, thirteen million, four hundred eleven thousand, three hundred fifty-one".
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