Base | Representation |
---|---|
bin | 1001110010001001110010… |
… | …01110100101011010011111 |
3 | 2211011202120002210021012212 |
4 | 10321010321032211122133 |
5 | 10304443044013411424 |
6 | 113431334045351035 |
7 | 4350240105533156 |
oct | 471047116453237 |
9 | 84152502707185 |
10 | 21514451310239 |
11 | 694525597a728 |
12 | 24b578a26847b |
13 | c00a5b674394 |
14 | 54543acc059d |
15 | 274990cb010e |
hex | 1391393a569f |
21514451310239 has 2 divisors, whose sum is σ = 21514451310240. Its totient is φ = 21514451310238.
The previous prime is 21514451310193. The next prime is 21514451310299. The reversal of 21514451310239 is 93201315441512.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21514451310239 - 212 = 21514451306143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21514451310196 and 21514451310205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21514451310299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757225655119 + 10757225655120.
It is an arithmetic number, because the mean of its divisors is an integer number (10757225655120).
Almost surely, 221514451310239 is an apocalyptic number.
21514451310239 is a deficient number, since it is larger than the sum of its proper divisors (1).
21514451310239 is an equidigital number, since it uses as much as digits as its factorization.
21514451310239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 21514451310239 in words is "twenty-one trillion, five hundred fourteen billion, four hundred fifty-one million, three hundred ten thousand, two hundred thirty-nine".
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