Base | Representation |
---|---|
bin | 11111010100010011111… |
… | …111110100100000000001 |
3 | 21121201222112101102000002 |
4 | 133110103333310200001 |
5 | 240230012203100023 |
6 | 4324400110205345 |
7 | 311325252061451 |
oct | 37242377644001 |
9 | 7551875342002 |
10 | 2152114112513 |
11 | 75a785346a62 |
12 | 2a91167b3855 |
13 | 127c35b03081 |
14 | 7623cd21d61 |
15 | 3aeac4b0b28 |
hex | 1f513ff4801 |
2152114112513 has 2 divisors, whose sum is σ = 2152114112514. Its totient is φ = 2152114112512.
The previous prime is 2152114112453. The next prime is 2152114112521. The reversal of 2152114112513 is 3152114112512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2102363702209 + 49750410304 = 1449953^2 + 223048^2 .
It is a cyclic number.
It is not a de Polignac number, because 2152114112513 - 220 = 2152113063937 is a prime.
It is not a weakly prime, because it can be changed into another prime (2152114112563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076057056256 + 1076057056257.
It is an arithmetic number, because the mean of its divisors is an integer number (1076057056257).
Almost surely, 22152114112513 is an apocalyptic number.
It is an amenable number.
2152114112513 is a deficient number, since it is larger than the sum of its proper divisors (1).
2152114112513 is an equidigital number, since it uses as much as digits as its factorization.
2152114112513 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2400, while the sum is 29.
Subtracting 2152114112513 from its reverse (3152114112512), we obtain a palindrome (999999999999).
The spelling of 2152114112513 in words is "two trillion, one hundred fifty-two billion, one hundred fourteen million, one hundred twelve thousand, five hundred thirteen".
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