Base | Representation |
---|---|
bin | 11111010100011111111… |
… | …010011000101000010111 |
3 | 21121202111110112110121102 |
4 | 133110133322120220113 |
5 | 240230414341423411 |
6 | 4324432010540315 |
7 | 311333230156343 |
oct | 37243772305027 |
9 | 7552443473542 |
10 | 2152314014231 |
11 | 75a878172097 |
12 | 2a917173769b |
13 | 127c68354704 |
14 | 7625b6ba623 |
15 | 3aebecead3b |
hex | 1f51fe98a17 |
2152314014231 has 2 divisors, whose sum is σ = 2152314014232. Its totient is φ = 2152314014230.
The previous prime is 2152314014203. The next prime is 2152314014251. The reversal of 2152314014231 is 1324104132512.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2152314014231 - 234 = 2135134145047 is a prime.
It is a super-2 number, since 2×21523140142312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2152314014194 and 2152314014203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2152314014251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076157007115 + 1076157007116.
It is an arithmetic number, because the mean of its divisors is an integer number (1076157007116).
Almost surely, 22152314014231 is an apocalyptic number.
2152314014231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2152314014231 is an equidigital number, since it uses as much as digits as its factorization.
2152314014231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 2152314014231 its reverse (1324104132512), we get a palindrome (3476418146743).
The spelling of 2152314014231 in words is "two trillion, one hundred fifty-two billion, three hundred fourteen million, fourteen thousand, two hundred thirty-one".
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