Base | Representation |
---|---|
bin | 1100100010100111100… |
… | …1000110111001001111 |
3 | 202121010011110000201221 |
4 | 3020221321012321033 |
5 | 12012221001413403 |
6 | 242551002544211 |
7 | 21365036664355 |
oct | 3105171067117 |
9 | 677104400657 |
10 | 215451201103 |
11 | 8341064a296 |
12 | 3590a208067 |
13 | 17417495818 |
14 | a5dc1d77d5 |
15 | 590ebb2dbd |
hex | 3229e46e4f |
215451201103 has 2 divisors, whose sum is σ = 215451201104. Its totient is φ = 215451201102.
The previous prime is 215451201079. The next prime is 215451201113. The reversal of 215451201103 is 301102154512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215451201103 - 225 = 215417646671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (215451201113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107725600551 + 107725600552.
It is an arithmetic number, because the mean of its divisors is an integer number (107725600552).
Almost surely, 2215451201103 is an apocalyptic number.
215451201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
215451201103 is an equidigital number, since it uses as much as digits as its factorization.
215451201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 215451201103 its reverse (301102154512), we get a palindrome (516553355615).
The spelling of 215451201103 in words is "two hundred fifteen billion, four hundred fifty-one million, two hundred one thousand, one hundred three".
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