Base | Representation |
---|---|
bin | 10100000111000011… |
… | …011111111011010111 |
3 | 2001201212101220211022 |
4 | 110013003133323113 |
5 | 323210324203244 |
6 | 13530401031355 |
7 | 1363046056643 |
oct | 240703377327 |
9 | 61655356738 |
10 | 21593194199 |
11 | 9180882445 |
12 | 422762555b |
13 | 20617999b5 |
14 | 108bb27c23 |
15 | 865a736ee |
hex | 5070dfed7 |
21593194199 has 2 divisors, whose sum is σ = 21593194200. Its totient is φ = 21593194198.
The previous prime is 21593194159. The next prime is 21593194223. The reversal of 21593194199 is 99149139512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21593194199 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21593194199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21593194159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10796597099 + 10796597100.
It is an arithmetic number, because the mean of its divisors is an integer number (10796597100).
Almost surely, 221593194199 is an apocalyptic number.
21593194199 is a deficient number, since it is larger than the sum of its proper divisors (1).
21593194199 is an equidigital number, since it uses as much as digits as its factorization.
21593194199 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 787320, while the sum is 53.
The spelling of 21593194199 in words is "twenty-one billion, five hundred ninety-three million, one hundred ninety-four thousand, one hundred ninety-nine".
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