Base | Representation |
---|---|
bin | 110001001100000110111011… |
… | …011000101110000010100011 |
3 | 1001100222112221022012001021222 |
4 | 301030012323120232002203 |
5 | 211323423321444123101 |
6 | 2044035314202405255 |
7 | 63365533315342052 |
oct | 6114067330560243 |
9 | 1040875838161258 |
10 | 216336351551651 |
11 | 62a27805634891 |
12 | 2031b52650082b |
13 | 9393579814166 |
14 | 3b5ca41890399 |
15 | 1a02611b7e01b |
hex | c4c1bb62e0a3 |
216336351551651 has 2 divisors, whose sum is σ = 216336351551652. Its totient is φ = 216336351551650.
The previous prime is 216336351551483. The next prime is 216336351551653. The reversal of 216336351551651 is 156155153633612.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-216336351551651 is a prime.
Together with 216336351551653, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 216336351551593 and 216336351551602.
It is not a weakly prime, because it can be changed into another prime (216336351551653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108168175775825 + 108168175775826.
It is an arithmetic number, because the mean of its divisors is an integer number (108168175775826).
Almost surely, 2216336351551651 is an apocalyptic number.
216336351551651 is a deficient number, since it is larger than the sum of its proper divisors (1).
216336351551651 is an equidigital number, since it uses as much as digits as its factorization.
216336351551651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7290000, while the sum is 53.
The spelling of 216336351551651 in words is "two hundred sixteen trillion, three hundred thirty-six billion, three hundred fifty-one million, five hundred fifty-one thousand, six hundred fifty-one".
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