Base | Representation |
---|---|
bin | 11111011111001000110… |
… | …101001101110101110101 |
3 | 21122211222121200012100122 |
4 | 133133020311031311311 |
5 | 240422313403142123 |
6 | 4334001341221325 |
7 | 312216305026334 |
oct | 37371065156565 |
9 | 7584877605318 |
10 | 2163737943413 |
11 | 7646aa72a182 |
12 | 2ab41b561845 |
13 | 12906904b317 |
14 | 76a229bdd1b |
15 | 3b43cbc8bc8 |
hex | 1f7c8d4dd75 |
2163737943413 has 2 divisors, whose sum is σ = 2163737943414. Its totient is φ = 2163737943412.
The previous prime is 2163737943337. The next prime is 2163737943431. The reversal of 2163737943413 is 3143497373612.
Together with next prime (2163737943431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2033082443044 + 130655500369 = 1425862^2 + 361463^2 .
It is a cyclic number.
It is not a de Polignac number, because 2163737943413 - 240 = 1064226315637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2163737943443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1081868971706 + 1081868971707.
It is an arithmetic number, because the mean of its divisors is an integer number (1081868971707).
Almost surely, 22163737943413 is an apocalyptic number.
It is an amenable number.
2163737943413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2163737943413 is an equidigital number, since it uses as much as digits as its factorization.
2163737943413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6858432, while the sum is 53.
The spelling of 2163737943413 in words is "two trillion, one hundred sixty-three billion, seven hundred thirty-seven million, nine hundred forty-three thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.100 sec. • engine limits •