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2164554656441 is a prime number
BaseRepresentation
bin11111011111111001100…
…000101110101010111001
321122221002112110112000022
4133133321200232222321
5240431001443001231
64334214354220225
7312245453002022
oct37377140565271
97587075415008
102164554656441
11764a89745821
122ab608b84675
13129169303478
1476a9d259c49
153b489752c7b
hex1f7f982eab9

2164554656441 has 2 divisors, whose sum is σ = 2164554656442. Its totient is φ = 2164554656440.

The previous prime is 2164554656423. The next prime is 2164554656443. The reversal of 2164554656441 is 1446564554612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2136026095225 + 28528561216 = 1461515^2 + 168904^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2164554656441 is a prime.

Together with 2164554656443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2164554656443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1082277328220 + 1082277328221.

It is an arithmetic number, because the mean of its divisors is an integer number (1082277328221).

Almost surely, 22164554656441 is an apocalyptic number.

It is an amenable number.

2164554656441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2164554656441 is an equidigital number, since it uses as much as digits as its factorization.

2164554656441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824000, while the sum is 53.

The spelling of 2164554656441 in words is "two trillion, one hundred sixty-four billion, five hundred fifty-four million, six hundred fifty-six thousand, four hundred forty-one".