Base | Representation |
---|---|
bin | 11111100110111010001… |
… | …110100100000011001011 |
3 | 21200122112012010002210202 |
4 | 133212322032210003023 |
5 | 241041411203124311 |
6 | 4341501402002415 |
7 | 312633144501002 |
oct | 37467216440313 |
9 | 7618465102722 |
10 | 2172082864331 |
11 | 7681a2172836 |
12 | 2b0b6a1a640b |
13 | 129a98b89853 |
14 | 771b4dd1c39 |
15 | 3b77a607e3b |
hex | 1f9ba3a40cb |
2172082864331 has 2 divisors, whose sum is σ = 2172082864332. Its totient is φ = 2172082864330.
The previous prime is 2172082864321. The next prime is 2172082864333. The reversal of 2172082864331 is 1334682802712.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2172082864331 is a prime.
It is a super-2 number, since 2×21720828643312 (a number of 25 digits) contains 22 as substring.
Together with 2172082864333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2172082864333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1086041432165 + 1086041432166.
It is an arithmetic number, because the mean of its divisors is an integer number (1086041432166).
Almost surely, 22172082864331 is an apocalyptic number.
2172082864331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2172082864331 is an equidigital number, since it uses as much as digits as its factorization.
2172082864331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 774144, while the sum is 47.
The spelling of 2172082864331 in words is "two trillion, one hundred seventy-two billion, eighty-two million, eight hundred sixty-four thousand, three hundred thirty-one".
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