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2175144347053 is a prime number
BaseRepresentation
bin11111101001110000101…
…101001100010110101101
321200221102112211112120201
4133221300231030112231
5241114143423101203
64343125244113501
7313102050614416
oct37516055142655
97627375745521
102175144347053
11769523307047
122b1683535891
1312a166219ba2
14773c584080d
153b8a9293e1d
hex1fa70b4c5ad

2175144347053 has 2 divisors, whose sum is σ = 2175144347054. Its totient is φ = 2175144347052.

The previous prime is 2175144347021. The next prime is 2175144347081. The reversal of 2175144347053 is 3507434415712.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2026856200329 + 148288146724 = 1423677^2 + 385082^2 .

It is a cyclic number.

It is not a de Polignac number, because 2175144347053 - 25 = 2175144347021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2175144346994 and 2175144347012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2175144347153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1087572173526 + 1087572173527.

It is an arithmetic number, because the mean of its divisors is an integer number (1087572173527).

Almost surely, 22175144347053 is an apocalyptic number.

It is an amenable number.

2175144347053 is a deficient number, since it is larger than the sum of its proper divisors (1).

2175144347053 is an equidigital number, since it uses as much as digits as its factorization.

2175144347053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1411200, while the sum is 46.

The spelling of 2175144347053 in words is "two trillion, one hundred seventy-five billion, one hundred forty-four million, three hundred forty-seven thousand, fifty-three".