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2175144347153 is a prime number
BaseRepresentation
bin11111101001110000101…
…101001100011000010001
321200221102112211112201102
4133221300231030120101
5241114143423102103
64343125244114145
7313102050614621
oct37516055143021
97627375745642
102175144347153
11769523307128
122b1683535955
1312a166219c4b
14773c5840881
153b8a9293e88
hex1fa70b4c611

2175144347153 has 2 divisors, whose sum is σ = 2175144347154. Its totient is φ = 2175144347152.

The previous prime is 2175144347107. The next prime is 2175144347203. The reversal of 2175144347153 is 3517434415712.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2079733168384 + 95411178769 = 1442128^2 + 308887^2 .

It is a cyclic number.

It is not a de Polignac number, because 2175144347153 - 28 = 2175144346897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2175144347098 and 2175144347107.

It is not a weakly prime, because it can be changed into another prime (2175144347053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1087572173576 + 1087572173577.

It is an arithmetic number, because the mean of its divisors is an integer number (1087572173577).

Almost surely, 22175144347153 is an apocalyptic number.

It is an amenable number.

2175144347153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2175144347153 is an equidigital number, since it uses as much as digits as its factorization.

2175144347153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1411200, while the sum is 47.

The spelling of 2175144347153 in words is "two trillion, one hundred seventy-five billion, one hundred forty-four million, three hundred forty-seven thousand, one hundred fifty-three".