Base | Representation |
---|---|
bin | 11111101111100100101… |
… | …000001110001010010000 |
3 | 21201112112102011021212012 |
4 | 133233210220032022100 |
5 | 241214433321334310 |
6 | 4350040345122052 |
7 | 313412506331435 |
oct | 37574450161220 |
9 | 7645472137765 |
10 | 2181384168080 |
11 | 771135548a27 |
12 | 2b2925189328 |
13 | 12a91bba3190 |
14 | 77818439b8c |
15 | 3bb21e9ec05 |
hex | 1fbe4a0e290 |
2181384168080 has 40 divisors (see below), whose sum is σ = 5461850361912. Its totient is φ = 805434153984.
The previous prime is 2181384167993. The next prime is 2181384168179. The reversal of 2181384168080 is 808614831812.
It can be written as a sum of positive squares in 4 ways, for example, as 1615396864 + 2179768771216 = 40192^2 + 1476404^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1048741349 + ... + 1048743428.
Almost surely, 22181384168080 is an apocalyptic number.
2181384168080 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2181384168080 is an abundant number, since it is smaller than the sum of its proper divisors (3280466193832).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2181384168080 is a wasteful number, since it uses less digits than its factorization.
2181384168080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2097484803 (or 2097484797 counting only the distinct ones).
The product of its (nonzero) digits is 589824, while the sum is 50.
Adding to 2181384168080 its reverse (808614831812), we get a palindrome (2989998999892).
The spelling of 2181384168080 in words is "two trillion, one hundred eighty-one billion, three hundred eighty-four million, one hundred sixty-eight thousand, eighty".
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