Base | Representation |
---|---|
bin | 11111110111100110011… |
… | …110000011001100000111 |
3 | 21202100210012202110022212 |
4 | 133313212132003030013 |
5 | 241340112234200402 |
6 | 4354024023214035 |
7 | 314136236164241 |
oct | 37674636031407 |
9 | 7670705673285 |
10 | 2190004990727 |
11 | 7748597a6644 |
12 | 2b45302a731b |
13 | 12b693c22878 |
14 | 77dd534b091 |
15 | 3be78c2c952 |
hex | 1fde6783307 |
2190004990727 has 2 divisors, whose sum is σ = 2190004990728. Its totient is φ = 2190004990726.
The previous prime is 2190004990669. The next prime is 2190004990729. The reversal of 2190004990727 is 7270994000912.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2190004990727 is a prime.
It is a super-2 number, since 2×21900049907272 (a number of 25 digits) contains 22 as substring.
Together with 2190004990729, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2190004990729) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1095002495363 + 1095002495364.
It is an arithmetic number, because the mean of its divisors is an integer number (1095002495364).
Almost surely, 22190004990727 is an apocalyptic number.
2190004990727 is a deficient number, since it is larger than the sum of its proper divisors (1).
2190004990727 is an equidigital number, since it uses as much as digits as its factorization.
2190004990727 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 571536, while the sum is 50.
The spelling of 2190004990727 in words is "two trillion, one hundred ninety billion, four million, nine hundred ninety thousand, seven hundred twenty-seven".
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