Base | Representation |
---|---|
bin | 1010000000010100011011… |
… | …10001010010111010101111 |
3 | 2212220021221112012111001102 |
4 | 11000022031301102322233 |
5 | 10340431424424000421 |
6 | 114443113500433315 |
7 | 4430351161612004 |
oct | 500121561227257 |
9 | 85807845174042 |
10 | 22001201000111 |
11 | 7012725437aa3 |
12 | 2573b9184883b |
13 | c379205cc858 |
14 | 560c1441b8ab |
15 | 28247d4ea60b |
hex | 14028dc52eaf |
22001201000111 has 2 divisors, whose sum is σ = 22001201000112. Its totient is φ = 22001201000110.
The previous prime is 22001201000071. The next prime is 22001201000113. The reversal of 22001201000111 is 11100010210022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22001201000111 - 210 = 22001200999087 is a prime.
Together with 22001201000113, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 22001201000092 and 22001201000101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22001201000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000600500055 + 11000600500056.
It is an arithmetic number, because the mean of its divisors is an integer number (11000600500056).
Almost surely, 222001201000111 is an apocalyptic number.
22001201000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
22001201000111 is an equidigital number, since it uses as much as digits as its factorization.
22001201000111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 22001201000111 its reverse (11100010210022), we get a palindrome (33101211210133).
The spelling of 22001201000111 in words is "twenty-two trillion, one billion, two hundred one million, one hundred eleven", and thus it is an aban number.
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