Base | Representation |
---|---|
bin | 110010000001101110101000… |
… | …101101010001000111111111 |
3 | 1001212000210222011022101001022 |
4 | 302001232220231101013333 |
5 | 212314311223222023403 |
6 | 2055540150204534355 |
7 | 64226000315330363 |
oct | 6201565055210777 |
9 | 1055023864271038 |
10 | 220021120111103 |
11 | 64118484400463 |
12 | 20815697b513bb |
13 | 959cb9702007c |
14 | 3c49116c1d2a3 |
15 | 1a683c319ad38 |
hex | c81ba8b511ff |
220021120111103 has 2 divisors, whose sum is σ = 220021120111104. Its totient is φ = 220021120111102.
The previous prime is 220021120111081. The next prime is 220021120111141. The reversal of 220021120111103 is 301111021120022.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 220021120111103 - 224 = 220021103333887 is a prime.
It is a super-3 number, since 3×2200211201111033 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (220021120111183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110010560055551 + 110010560055552.
It is an arithmetic number, because the mean of its divisors is an integer number (110010560055552).
Almost surely, 2220021120111103 is an apocalyptic number.
220021120111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
220021120111103 is an equidigital number, since it uses as much as digits as its factorization.
220021120111103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 220021120111103 its reverse (301111021120022), we get a palindrome (521132141231125).
The spelling of 220021120111103 in words is "two hundred twenty trillion, twenty-one billion, one hundred twenty million, one hundred eleven thousand, one hundred three".
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