Base | Representation |
---|---|
bin | 1010000000011000000000… |
… | …10010100011111100000111 |
3 | 2212220110220102111210212002 |
4 | 11000030000102203330013 |
5 | 10340444343303320312 |
6 | 114444032253215515 |
7 | 4430446611601034 |
oct | 500140022437407 |
9 | 85813812453762 |
10 | 22003122323207 |
11 | 7013520a27523 |
12 | 257442919159b |
13 | c37b6868ab1c |
14 | 560d5767638b |
15 | 28254201b4c2 |
hex | 1403004a3f07 |
22003122323207 has 2 divisors, whose sum is σ = 22003122323208. Its totient is φ = 22003122323206.
The previous prime is 22003122323201. The next prime is 22003122323209. The reversal of 22003122323207 is 70232322130022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22003122323207 - 210 = 22003122322183 is a prime.
Together with 22003122323209, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 22003122323207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22003122323201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11001561161603 + 11001561161604.
It is an arithmetic number, because the mean of its divisors is an integer number (11001561161604).
Almost surely, 222003122323207 is an apocalyptic number.
22003122323207 is a deficient number, since it is larger than the sum of its proper divisors (1).
22003122323207 is an equidigital number, since it uses as much as digits as its factorization.
22003122323207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 29.
Adding to 22003122323207 its reverse (70232322130022), we get a palindrome (92235444453229).
The spelling of 22003122323207 in words is "twenty-two trillion, three billion, one hundred twenty-two million, three hundred twenty-three thousand, two hundred seven".
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