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220100111001013 is a prime number
BaseRepresentation
bin110010000010111000001100…
…111011100110010110110101
31001212022100212011121100020111
4302002320030323212112311
5212322110011404013023
62100040332313503021
764234464634656145
oct6202701473462665
91055270764540214
10220100111001013
1164148a29731161
1220828a61a11a71
1395a7475078209
143c4cc8b958925
151a6a497c8900d
hexc82e0cee65b5

220100111001013 has 2 divisors, whose sum is σ = 220100111001014. Its totient is φ = 220100111001012.

The previous prime is 220100111000893. The next prime is 220100111001103. The reversal of 220100111001013 is 310100111001022.

It is a happy number.

220100111001013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (220100111001103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130993930686564 + 89106180314449 = 11445258^2 + 9439607^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-220100111001013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 220100111000984 and 220100111001002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (220100111005013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110050055500506 + 110050055500507.

It is an arithmetic number, because the mean of its divisors is an integer number (110050055500507).

Almost surely, 2220100111001013 is an apocalyptic number.

It is an amenable number.

220100111001013 is a deficient number, since it is larger than the sum of its proper divisors (1).

220100111001013 is an equidigital number, since it uses as much as digits as its factorization.

220100111001013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 220100111001013 its reverse (310100111001022), we get a palindrome (530200222002035).

Subtracting 220100111001013 from its reverse (310100111001022), we obtain a palindrome (90000000000009).

The spelling of 220100111001013 in words is "two hundred twenty trillion, one hundred billion, one hundred eleven million, one thousand, thirteen".