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220121454052433 is a prime number
BaseRepresentation
bin110010000011001100000101…
…000100111000010001010001
31001212101101221121022200200102
4302003030011010320101101
5212322432214214134213
62100054222221302145
764236151555630643
oct6203140504702121
91055341847280612
10220121454052433
1164156a9129262a
1220831019704955
1395a9496a8251b
143c4dd1436a893
151a6ace689b158
hexc83305138451

220121454052433 has 2 divisors, whose sum is σ = 220121454052434. Its totient is φ = 220121454052432.

The previous prime is 220121454052361. The next prime is 220121454052471. The reversal of 220121454052433 is 334250454121022.

It is an a-pointer prime, because the next prime (220121454052471) can be obtained adding 220121454052433 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111566976625729 + 108554477426704 = 10562527^2 + 10418948^2 .

It is a cyclic number.

It is not a de Polignac number, because 220121454052433 - 28 = 220121454052177 is a prime.

It is not a weakly prime, because it can be changed into another prime (220121454352433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110060727026216 + 110060727026217.

It is an arithmetic number, because the mean of its divisors is an integer number (110060727026217).

Almost surely, 2220121454052433 is an apocalyptic number.

It is an amenable number.

220121454052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

220121454052433 is an equidigital number, since it uses as much as digits as its factorization.

220121454052433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

The spelling of 220121454052433 in words is "two hundred twenty trillion, one hundred twenty-one billion, four hundred fifty-four million, fifty-two thousand, four hundred thirty-three".