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220131021223051 is a prime number
BaseRepresentation
bin110010000011010100111111…
…010100101111010010001011
31001212102022122100122022111221
4302003110333110233102023
5212323111312413114201
62100102443423102511
764236640626346441
oct6203247724572213
91055368570568457
10220131021223051
1164160050749504
1220832a49741a37
1395aa35cba5623
143c50580c20b91
151a6b1a675d4a1
hexc8353f52f48b

220131021223051 has 2 divisors, whose sum is σ = 220131021223052. Its totient is φ = 220131021223050.

The previous prime is 220131021223049. The next prime is 220131021223177. The reversal of 220131021223051 is 150322120131022.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 220131021223051 - 21 = 220131021223049 is a prime.

Together with 220131021223049, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (220131021233051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110065510611525 + 110065510611526.

It is an arithmetic number, because the mean of its divisors is an integer number (110065510611526).

Almost surely, 2220131021223051 is an apocalyptic number.

220131021223051 is a deficient number, since it is larger than the sum of its proper divisors (1).

220131021223051 is an equidigital number, since it uses as much as digits as its factorization.

220131021223051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 220131021223051 its reverse (150322120131022), we get a palindrome (370453141354073).

The spelling of 220131021223051 in words is "two hundred twenty trillion, one hundred thirty-one billion, twenty-one million, two hundred twenty-three thousand, fifty-one".