Base | Representation |
---|---|
bin | 110010000011010100111111… |
… | …010100101111010010001011 |
3 | 1001212102022122100122022111221 |
4 | 302003110333110233102023 |
5 | 212323111312413114201 |
6 | 2100102443423102511 |
7 | 64236640626346441 |
oct | 6203247724572213 |
9 | 1055368570568457 |
10 | 220131021223051 |
11 | 64160050749504 |
12 | 20832a49741a37 |
13 | 95aa35cba5623 |
14 | 3c50580c20b91 |
15 | 1a6b1a675d4a1 |
hex | c8353f52f48b |
220131021223051 has 2 divisors, whose sum is σ = 220131021223052. Its totient is φ = 220131021223050.
The previous prime is 220131021223049. The next prime is 220131021223177. The reversal of 220131021223051 is 150322120131022.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 220131021223051 - 21 = 220131021223049 is a prime.
Together with 220131021223049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (220131021233051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110065510611525 + 110065510611526.
It is an arithmetic number, because the mean of its divisors is an integer number (110065510611526).
Almost surely, 2220131021223051 is an apocalyptic number.
220131021223051 is a deficient number, since it is larger than the sum of its proper divisors (1).
220131021223051 is an equidigital number, since it uses as much as digits as its factorization.
220131021223051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 220131021223051 its reverse (150322120131022), we get a palindrome (370453141354073).
The spelling of 220131021223051 in words is "two hundred twenty trillion, one hundred thirty-one billion, twenty-one million, two hundred twenty-three thousand, fifty-one".
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