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22111065904493 is a prime number
BaseRepresentation
bin1010000011100001000100…
…01110101001010101101101
32220021210112012101220002002
411001300202032221111231
510344231430332420433
6115005403342542045
74441320553106456
oct501604216512555
986253465356062
1022111065904493
1170552832a5835
122591333297925
13c450abb18807
145662776b612d
1528525d8099e8
hex141c223a956d

22111065904493 has 2 divisors, whose sum is σ = 22111065904494. Its totient is φ = 22111065904492.

The previous prime is 22111065904381. The next prime is 22111065904559. The reversal of 22111065904493 is 39440956011122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11617211010409 + 10493854894084 = 3408403^2 + 3239422^2 .

It is a cyclic number.

It is not a de Polignac number, because 22111065904493 - 28 = 22111065904237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22111065907493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11055532952246 + 11055532952247.

It is an arithmetic number, because the mean of its divisors is an integer number (11055532952247).

Almost surely, 222111065904493 is an apocalyptic number.

It is an amenable number.

22111065904493 is a deficient number, since it is larger than the sum of its proper divisors (1).

22111065904493 is an equidigital number, since it uses as much as digits as its factorization.

22111065904493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 47.

The spelling of 22111065904493 in words is "twenty-two trillion, one hundred eleven billion, sixty-five million, nine hundred four thousand, four hundred ninety-three".