Base | Representation |
---|---|
bin | 110010010010111001101101… |
… | …011001101100101111101101 |
3 | 1002000012122001211012201020221 |
4 | 302102321231121230233231 |
5 | 212443130120212211023 |
6 | 2102242240342011341 |
7 | 64410155651442232 |
oct | 6222715531545755 |
9 | 1060178054181227 |
10 | 221201241132013 |
11 | 64532a12a0730a |
12 | 20986348116b51 |
13 | 965725902394c |
14 | 3c8a2a9165789 |
15 | 1a88e42a7385d |
hex | c92e6d66cbed |
221201241132013 has 2 divisors, whose sum is σ = 221201241132014. Its totient is φ = 221201241132012.
The previous prime is 221201241131953. The next prime is 221201241132017. The reversal of 221201241132013 is 310231142102122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 188429073940809 + 32772167191204 = 13726947^2 + 5724698^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-221201241132013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (221201241132017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110600620566006 + 110600620566007.
It is an arithmetic number, because the mean of its divisors is an integer number (110600620566007).
Almost surely, 2221201241132013 is an apocalyptic number.
It is an amenable number.
221201241132013 is a deficient number, since it is larger than the sum of its proper divisors (1).
221201241132013 is an equidigital number, since it uses as much as digits as its factorization.
221201241132013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 221201241132013 its reverse (310231142102122), we get a palindrome (531432383234135).
The spelling of 221201241132013 in words is "two hundred twenty-one trillion, two hundred one billion, two hundred forty-one million, one hundred thirty-two thousand, thirteen".
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