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221201241132013 is a prime number
BaseRepresentation
bin110010010010111001101101…
…011001101100101111101101
31002000012122001211012201020221
4302102321231121230233231
5212443130120212211023
62102242240342011341
764410155651442232
oct6222715531545755
91060178054181227
10221201241132013
1164532a12a0730a
1220986348116b51
13965725902394c
143c8a2a9165789
151a88e42a7385d
hexc92e6d66cbed

221201241132013 has 2 divisors, whose sum is σ = 221201241132014. Its totient is φ = 221201241132012.

The previous prime is 221201241131953. The next prime is 221201241132017. The reversal of 221201241132013 is 310231142102122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 188429073940809 + 32772167191204 = 13726947^2 + 5724698^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-221201241132013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (221201241132017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110600620566006 + 110600620566007.

It is an arithmetic number, because the mean of its divisors is an integer number (110600620566007).

Almost surely, 2221201241132013 is an apocalyptic number.

It is an amenable number.

221201241132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

221201241132013 is an equidigital number, since it uses as much as digits as its factorization.

221201241132013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 221201241132013 its reverse (310231142102122), we get a palindrome (531432383234135).

The spelling of 221201241132013 in words is "two hundred twenty-one trillion, two hundred one billion, two hundred forty-one million, one hundred thirty-two thousand, thirteen".