Base | Representation |
---|---|
bin | 1010000011110001111111… |
… | …01011111010100111100111 |
3 | 2220022122222021211100210221 |
4 | 11001320333223322213213 |
5 | 10344404031403120203 |
6 | 115013505011425211 |
7 | 4442061640064503 |
oct | 501707753724747 |
9 | 86278867740727 |
10 | 22120150051303 |
11 | 705911503a787 |
12 | 25930495b5207 |
13 | c45bc8b4b805 |
14 | 566899d53303 |
15 | 2855e10a8abd |
hex | 141e3fafa9e7 |
22120150051303 has 2 divisors, whose sum is σ = 22120150051304. Its totient is φ = 22120150051302.
The previous prime is 22120150051171. The next prime is 22120150051309. The reversal of 22120150051303 is 30315005102122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22120150051303 - 225 = 22120116496871 is a prime.
It is a super-2 number, since 2×221201500513032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22120150051309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11060075025651 + 11060075025652.
It is an arithmetic number, because the mean of its divisors is an integer number (11060075025652).
Almost surely, 222120150051303 is an apocalyptic number.
22120150051303 is a deficient number, since it is larger than the sum of its proper divisors (1).
22120150051303 is an equidigital number, since it uses as much as digits as its factorization.
22120150051303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 22120150051303 its reverse (30315005102122), we get a palindrome (52435155153425).
The spelling of 22120150051303 in words is "twenty-two trillion, one hundred twenty billion, one hundred fifty million, fifty-one thousand, three hundred three".
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