Base | Representation |
---|---|
bin | 100000001100000111111… |
… | …100010101001101011111 |
3 | 21211110122222011201102012 |
4 | 200030013330111031133 |
5 | 242220230100212341 |
6 | 4412110420221435 |
7 | 315546306531551 |
oct | 40140774251537 |
9 | 7743588151365 |
10 | 2212041413471 |
11 | 78313778a16a |
12 | 2b886023a87b |
13 | 130796488076 |
14 | 790c5c8d4d1 |
15 | 3c8186530eb |
hex | 20307f1535f |
2212041413471 has 2 divisors, whose sum is σ = 2212041413472. Its totient is φ = 2212041413470.
The previous prime is 2212041413423. The next prime is 2212041413501. The reversal of 2212041413471 is 1743141402122.
2212041413471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2212041413471 - 222 = 2212037219167 is a prime.
It is a super-3 number, since 3×22120414134713 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2212041413671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106020706735 + 1106020706736.
It is an arithmetic number, because the mean of its divisors is an integer number (1106020706736).
Almost surely, 22212041413471 is an apocalyptic number.
2212041413471 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212041413471 is an equidigital number, since it uses as much as digits as its factorization.
2212041413471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 32.
Adding to 2212041413471 its reverse (1743141402122), we get a palindrome (3955182815593).
The spelling of 2212041413471 in words is "two trillion, two hundred twelve billion, forty-one million, four hundred thirteen thousand, four hundred seventy-one".
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