Base | Representation |
---|---|
bin | 110010100000001010111101… |
… | …101111101001100010100111 |
3 | 1002010102210210101012000212222 |
4 | 302200022331233221202213 |
5 | 213103100133231130322 |
6 | 2104221205404302555 |
7 | 64533100140153146 |
oct | 6240127557514247 |
9 | 1063383711160788 |
10 | 222113122130087 |
11 | 64854711a68881 |
12 | 20ab3017241a5b |
13 | 96c22400a9a16 |
14 | 3cbc49242d75d |
15 | 1aa2a13165e42 |
hex | ca02bdbe98a7 |
222113122130087 has 2 divisors, whose sum is σ = 222113122130088. Its totient is φ = 222113122130086.
The previous prime is 222113122130033. The next prime is 222113122130089. The reversal of 222113122130087 is 780031221311222.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 222113122130087 - 242 = 217715075618983 is a prime.
Together with 222113122130089, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (222113122130089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111056561065043 + 111056561065044.
It is an arithmetic number, because the mean of its divisors is an integer number (111056561065044).
Almost surely, 2222113122130087 is an apocalyptic number.
222113122130087 is a deficient number, since it is larger than the sum of its proper divisors (1).
222113122130087 is an equidigital number, since it uses as much as digits as its factorization.
222113122130087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 222113122130087 in words is "two hundred twenty-two trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred thirty thousand, eighty-seven".
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