Base | Representation |
---|---|
bin | 110010100000001100000110… |
… | …011010001100100110100111 |
3 | 1002010102220221100011101211022 |
4 | 302200030012122030212213 |
5 | 213103110132324241203 |
6 | 2104221530354201355 |
7 | 64533142302355115 |
oct | 6240140632144647 |
9 | 1063386840141738 |
10 | 222114341243303 |
11 | 64855188139663 |
12 | 20ab32b758325b |
13 | 96c23a5833aa2 |
14 | 3cbc56a2d6ab5 |
15 | 1aa2a851c9a38 |
hex | ca030668c9a7 |
222114341243303 has 2 divisors, whose sum is σ = 222114341243304. Its totient is φ = 222114341243302.
The previous prime is 222114341243257. The next prime is 222114341243321. The reversal of 222114341243303 is 303342143411222.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 222114341243303 - 212 = 222114341239207 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (222114341243363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111057170621651 + 111057170621652.
It is an arithmetic number, because the mean of its divisors is an integer number (111057170621652).
Almost surely, 2222114341243303 is an apocalyptic number.
222114341243303 is a deficient number, since it is larger than the sum of its proper divisors (1).
222114341243303 is an equidigital number, since it uses as much as digits as its factorization.
222114341243303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 222114341243303 its reverse (303342143411222), we get a palindrome (525456484654525).
The spelling of 222114341243303 in words is "two hundred twenty-two trillion, one hundred fourteen billion, three hundred forty-one million, two hundred forty-three thousand, three hundred three".
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