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22311052117 is a prime number
BaseRepresentation
bin10100110001110101…
…111010001101010101
32010120220011212202121
4110301311322031111
5331143112131432
614125523135541
71416613546114
oct246165721525
963526155677
1022311052117
11950a009752
1243a7b145b1
13214741c4b3
1411191cdc7b
158a8ac2197
hex531d7a355

22311052117 has 2 divisors, whose sum is σ = 22311052118. Its totient is φ = 22311052116.

The previous prime is 22311052109. The next prime is 22311052177. The reversal of 22311052117 is 71125011322.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20814987076 + 1496065041 = 144274^2 + 38679^2 .

It is a cyclic number.

It is not a de Polignac number, because 22311052117 - 23 = 22311052109 is a prime.

It is a super-3 number, since 3×223110521173 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 22311052091 and 22311052100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22311052177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11155526058 + 11155526059.

It is an arithmetic number, because the mean of its divisors is an integer number (11155526059).

Almost surely, 222311052117 is an apocalyptic number.

It is an amenable number.

22311052117 is a deficient number, since it is larger than the sum of its proper divisors (1).

22311052117 is an equidigital number, since it uses as much as digits as its factorization.

22311052117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 22311052117 its reverse (71125011322), we get a palindrome (93436063439).

The spelling of 22311052117 in words is "twenty-two billion, three hundred eleven million, fifty-two thousand, one hundred seventeen".