Base | Representation |
---|---|
bin | 1010001001010111101111… |
… | …00011000100101101010111 |
3 | 2221000000201111201102012021 |
4 | 11010223313203010231113 |
5 | 10411030403101131403 |
6 | 115242031141434011 |
7 | 4462001305555144 |
oct | 504536743045527 |
9 | 87000644642167 |
10 | 22312213302103 |
11 | 712261380481a |
12 | 260430b10b907 |
13 | c5b056a7238a |
14 | 571cb9d133cb |
15 | 28a5d28788bd |
hex | 144af78c4b57 |
22312213302103 has 2 divisors, whose sum is σ = 22312213302104. Its totient is φ = 22312213302102.
The previous prime is 22312213302073. The next prime is 22312213302179. The reversal of 22312213302103 is 30120331221322.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22312213302103 - 221 = 22312211204951 is a prime.
It is a super-3 number, since 3×223122133021033 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22312213302403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11156106651051 + 11156106651052.
It is an arithmetic number, because the mean of its divisors is an integer number (11156106651052).
Almost surely, 222312213302103 is an apocalyptic number.
22312213302103 is a deficient number, since it is larger than the sum of its proper divisors (1).
22312213302103 is an equidigital number, since it uses as much as digits as its factorization.
22312213302103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 22312213302103 its reverse (30120331221322), we get a palindrome (52432544523425).
The spelling of 22312213302103 in words is "twenty-two trillion, three hundred twelve billion, two hundred thirteen million, three hundred two thousand, one hundred three".
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