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22314241174331 is a prime number
BaseRepresentation
bin1010001001011011100000…
…11010110010101100111011
32221000012221211111222221002
411010231300122302230323
510411044031220034311
6115243004302035215
74462102461314111
oct504556032625473
987005854458832
1022314241174331
117123464459187
122604796278b0b
13c5b2bac28082
1457202d385ab1
1528a6a08e493b
hex144b706b2b3b

22314241174331 has 2 divisors, whose sum is σ = 22314241174332. Its totient is φ = 22314241174330.

The previous prime is 22314241174321. The next prime is 22314241174333. The reversal of 22314241174331 is 13347114241322.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 22314241174331 - 226 = 22314174065467 is a prime.

It is a super-3 number, since 3×223142411743313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 22314241174333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (22314241174333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11157120587165 + 11157120587166.

It is an arithmetic number, because the mean of its divisors is an integer number (11157120587166).

Almost surely, 222314241174331 is an apocalyptic number.

22314241174331 is a deficient number, since it is larger than the sum of its proper divisors (1).

22314241174331 is an equidigital number, since it uses as much as digits as its factorization.

22314241174331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96768, while the sum is 38.

The spelling of 22314241174331 in words is "twenty-two trillion, three hundred fourteen billion, two hundred forty-one million, one hundred seventy-four thousand, three hundred thirty-one".