Base | Representation |
---|---|
bin | 1010001001100110111000… |
… | …00000001011001100101111 |
3 | 2221000210200221121111112012 |
4 | 11010303130000023030233 |
5 | 10411144024310302112 |
6 | 115245453444431435 |
7 | 4462406601000644 |
oct | 504633400131457 |
9 | 87023627544465 |
10 | 22320341103407 |
11 | 7126004732186 |
12 | 26059b90a857b |
13 | c5ba50911269 |
14 | 57244b567dcb |
15 | 28a90b1bb022 |
hex | 144cdc00b32f |
22320341103407 has 2 divisors, whose sum is σ = 22320341103408. Its totient is φ = 22320341103406.
The previous prime is 22320341103289. The next prime is 22320341103469. The reversal of 22320341103407 is 70430114302322.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22320341103407 - 210 = 22320341102383 is a prime.
It is a super-3 number, since 3×223203411034073 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22320341105407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11160170551703 + 11160170551704.
It is an arithmetic number, because the mean of its divisors is an integer number (11160170551704).
Almost surely, 222320341103407 is an apocalyptic number.
22320341103407 is a deficient number, since it is larger than the sum of its proper divisors (1).
22320341103407 is an equidigital number, since it uses as much as digits as its factorization.
22320341103407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 22320341103407 its reverse (70430114302322), we get a palindrome (92750455405729).
The spelling of 22320341103407 in words is "twenty-two trillion, three hundred twenty billion, three hundred forty-one million, one hundred three thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •