Base | Representation |
---|---|
bin | 1000010101101100… |
… | …1100110100010001 |
3 | 12210000010120212121 |
4 | 2011123030310101 |
5 | 14041024000423 |
6 | 1010042454241 |
7 | 106320636253 |
oct | 20533146421 |
9 | 5700116777 |
10 | 2238500113 |
11 | a496362a3 |
12 | 525804381 |
13 | 2989c15a5 |
14 | 17341dcd3 |
15 | d17c445d |
hex | 856ccd11 |
2238500113 has 2 divisors, whose sum is σ = 2238500114. Its totient is φ = 2238500112.
The previous prime is 2238500107. The next prime is 2238500119. The reversal of 2238500113 is 3110058322.
It is a balanced prime because it is at equal distance from previous prime (2238500107) and next prime (2238500119).
It can be written as a sum of positive squares in only one way, i.e., 1888510849 + 349989264 = 43457^2 + 18708^2 .
It is a cyclic number.
It is not a de Polignac number, because 2238500113 - 213 = 2238491921 is a prime.
It is not a weakly prime, because it can be changed into another prime (2238500119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1119250056 + 1119250057.
It is an arithmetic number, because the mean of its divisors is an integer number (1119250057).
Almost surely, 22238500113 is an apocalyptic number.
It is an amenable number.
2238500113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2238500113 is an equidigital number, since it uses as much as digits as its factorization.
2238500113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 2238500113 is about 47312.7901629147. The cubic root of 2238500113 is about 1308.1344213790.
Adding to 2238500113 its reverse (3110058322), we get a palindrome (5348558435).
The spelling of 2238500113 in words is "two billion, two hundred thirty-eight million, five hundred thousand, one hundred thirteen".
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